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Question
If the sum of the roots of the equation `kx^2+2x+3k=0` is equal to their product then the value of k
`(a) 1/3 (b)-1/3 (c)2/3 (d)-2/3`
Solution
Given:
`kx^2+2x+3k=0`
Sum of the roots = Product of the roots
⇒ `-2/k=(3k)/k`
⇒ `3k=-2`
⇒` k=(-2)/3`
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