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Question
The roots of a quadratic equation are 5 and -2. Then, the equation is
(a)`x^2-3x+10=0` (b)`x^2-3x-10=0` (c)x^2+3x-10=0 (d)`x^2+3x+10=0`
Solution
(b)` x^2-3x-10=0`
It is given that the roots of the quadratic equation are 5 and . 2 Then, the equation is:
`x^2-(5-2)x+5xx(-2)=0`
⇒` x^2-3x-10=0`
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