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Question
If the 3rd and the 9th term of an A.P. be 4 and –8 respectively, find which term is zero?
Solution
For an A.P., a
t3 = 4
`=>` a + 2d = 4 ...(i)
t9 = – 8
`=>` a + 8d = – 8 ...(ii)
Subtracting (i) from (ii), we get
6d = –12
`=>` d = –2
Substituting d = –2 in (i), we get
a + 2(–2) = 4
`=>` a – 4 = 4
`=>` a = 8
`=>` General term = tn = 8 + (n – 1)(–2)
Let pth term of this A.P. be 0
`=>` 8 + (p – 1) × (–2) = 0
`=>` 8 – 2p + 2 = o
`=>` 10 – 2p = 0
`=>` 2p = 10
`=>` p = 5
Thus, 5th term of this A.P. is 0
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