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Question
If the demand function is D = 50 – 3p – p2. Find the elasticity of demand at p = 2 comment on the result
Solution
Given, demand function is D = 50 – 3p – p2
∴ `"dD"/"dp" = 0 - 3 - 2"p"`
= `- 3 - 2"p"`
Elasticity of demand is given by
`eta =- ("p")/"D" * "dD"/"dp"`
∴ `eta = (-"p")/(50 - 3"p" - "p"^2) * (- 3 - 2"p")`
∴ `eta = (p(3 + 2p))/(50 - 3p - p^2)`
(i) When p = 5
`eta = (5(3 + 2xx 5))/(50 - 3(5) - (5)^2) = (5xx13)/(50 - 15 - 25)`
= `65/10 = 6.5`
Since η > 1 the demand is elastic
(ii) When p = 2 then,
`eta = (2(3 + 2 xx 2))/(50 - 3(2) - (2)^2) = (2xx7)/(50 -6 - 4)`
= `14/40 = 7/20`
Since, < η < 1, the demand is inelastic.
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Fill in the blank:
A road of 108 m length is bent to form a rectangle. If the area of the rectangle is maximum, then its dimensions are _______.
If the elasticity of demand η = 1, then demand is ______.
If 0 < η < 1, then the demand is ______.
If the average revenue is 45 and elasticity of demand is 5, then marginal revenue is ______.
State whether the following statement is True or False:
If the marginal revenue is 50 and the price is ₹ 75, then elasticity of demand is 4
If f(x) = x3 – 3x2 + 3x – 100, x ∈ R then f"(x) is ______.
If 0 < η < 1 then the demand is ______.
In a factory, for production of Q articles, standing charges are ₹500, labour charges are ₹700 and processing charges are 50Q. The price of an article is 1700 - 3Q. Complete the following activity to find the values of Q for which the profit is increasing.
Solution: Let C be the cost of production of Q articles.
Then C = standing charges + labour charges + processing charges
∴ C = `square`
Revenue R = P·Q = (1700 - 3Q)Q = 1700Q- 3Q2
Profit `pi = R - C = square`
Differentiating w.r.t. Q, we get
`(dpi)/(dQ) = square`
If profit is increasing , then `(dpi)/(dQ) >0`
∴ `Q < square`
Hence, profit is increasing for `Q < square`