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Question
If x is 30% more than y; find : `"y"/("y" - "x")`
Solution
Let y = a
Then x = `"a" xx (100 + 30)/100`
`= "a" xx 130/100 = 13/10 "a"`
Now, `"y"/("y" - "x")`
` = "a"/("a" - 13/10"a") = "a"/(-3/10 "a")`
`= ("a" xx 10)/(- 3"a") = - 10/3`
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