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Question
If x is 30% more than y; find : `("y" + "x")/"x"`
Solution
Let y = a
Then x = `"a" xx (100 + 30)/100`
`= "a" xx 130/100 = 13/10 "a"`
Now, `("y" + "x")/"x"`
`= ("a" + 13/10 "a")/(13/10 "a")`
`= ((10 + 13)"a")/(10 xx 13/10 "a")`
`= "23 a"/10 xx 10/"13 a" = 23/13`
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