Advertisements
Advertisements
Question
If x3 + 6x2 + 4x + k is exactly divisible by x + 2, then k =
Options
−6
−7
−8
−10
Solution
As f(x) = x3 + 6x2 + 4x + k is exactly divisible by (x +2).
i.e., ( x+2)is a factor of f(x).
Therefore, f(-2) =0
`(-2)^3 + 6(-2)^2 + 4(-2) + k = 0`
`-8 +24 - 8+ k = 0`
` = -8`
APPEARS IN
RELATED QUESTIONS
Identify polynomials in the following:
`h(x)=x^4-x^(3/2)+x-1`
Find the remainder when x3 + 3x2 + 3x + 1 is divided by x + 1.
f(x) = 2x3 − 9x2 + x + 12, g(x) = 3 − 2x
In the following two polynomials, find the value of a, if x − a is factor x6 − ax5 + x4 − ax3 + 3x − a + 2.
y3 − 2y2 − 29y − 42
2y3 + y2 − 2y − 1
When x3 − 2x2 + ax − b is divided by x2 − 2x − 3, the remainder is x − 6. The values of a and b are respectively
Factorise the following:
6x2 + 16xy + 8y2
(x + y)(x2 – xy + y2) is equal to
Factorise:
2x3 – 3x2 – 17x + 30
