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प्रश्न
If x3 + 6x2 + 4x + k is exactly divisible by x + 2, then k =
विकल्प
−6
−7
−8
−10
उत्तर
As f(x) = x3 + 6x2 + 4x + k is exactly divisible by (x +2).
i.e., ( x+2)is a factor of f(x).
Therefore, f(-2) =0
`(-2)^3 + 6(-2)^2 + 4(-2) + k = 0`
`-8 +24 - 8+ k = 0`
` = -8`
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