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Question
If z = x + iy, find the following in rectangular form:
`"Re"(1/z)`
Solution
`"Re"(1/z) = 1/(x + "i"y) xx (x - "i"y)/(x - "i"y)`
= `(x - "i"y)/(x^2 + y^2)`
= `x/(x^2 + y^2) - ("i"y)/(x^2 + y^2)`
∴ `"Re"(1/z) = x/(x^2 + y^2)`
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