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Question
In a hostel, 60% of the students read Hindi newspaper, 40% read English newspaper and 20% read both Hindi and English news papers. A student is selected at random.
If she reads Hindi news paper, find the probability that she reads English news paper.
Solution
Let H = the event of reading a Hindi newspaper,
E = event of reading an English newspaper
Then P(H) = `60/100 = 3/5`, P(E) = `40/100 = 2/5`
and P(H ∩ E) = `20/100 = 1/5`
Process of desired event = P(E|H) = `(P(E ∩ H))/(P(H))`
= `(1/5)/(3/5)`
= `1/3`
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