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Question
In the adjoining figure, point O is the centre of the cirlcle, seg OM ⊥ chord AB. If OM = 8cm, AB = 12 cm, then find OB.
Solution
MB = 12 × AB = 12 × 12 = 6 cm (perpendicular drawn from the centre of the circle to the chord bisects the chord)
`OB^ = OM^2 + MB^2` .....................(Pythagoras thearem)
= `8^2 + 6^2`
= 64 + 36 = 100
∴ OB = 10 cm
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