Advertisements
Advertisements
Question
In the following data, one of the values of Y is missing. Arithmetic means of X and Y series are 6 and 8
X |
6 |
2 |
10 |
4 |
8 |
Y |
9 |
11 |
? |
8 |
7 |
(a) Estimate the missing observation.
(b) Calculate correlation coefficient.
Solution
(a)First, we find the missing value of Y and let us denote it by a.
`barY=(SigmaY)/N=(9+11+a+8+7)/5=(35+a)/5`
`=>8=(35+a)/5=>40=35+a=>a=5`
Thus the completed series is
X | 6 | 2 | 10 | 4 | 8 |
Y | 9 | 11 | 5 | 8 | 7 |
(b)Now we Find coefficient correlation
xi | yi | xiyi | `x_i^2` | `y_i^2` |
6 | 9 | 54 | 36 | 81 |
2 | 11 | 22 | 4 | 121 |
10 | 5 | 50 | 100 | 25 |
4 | 8 | 32 | 16 | 64 |
8 | 7 | 56 | 64 | 49 |
Σxi = 30 | Σyi = 40 | Σxiyi = 214 | Σ`x_i^2`=220 | Σ`y_i^2` = 340 |
Here, n= 5, ΣX = 30, Σx2 = 40, ΣY=40, ΣY2 = 20 and Σxy = -26
Now,
`barX = (SigmaX)/n =30/5=6 " and "barY =(SigmaY)/n=40/5=8`
`:. r = (1/n Σ x iyi - barx bary)/(sqrt[[(Σxi^2)/n - barx^2] [(Σyi^2)/n - bary^2]`
`r = (1/5 xx 214 - 8 xx 6)/(sqrt(220/5 - 6^2) xx sqrt(340/5 - 8^2)`
`= (42.8 - 48)/((sqrt (44 - 36) xx sqrt(68 - 64))`
= `(-5.2)/(sqrt8 xx sqrt4)`
= `(-5.2)/(4sqrt2)`
r = -0.92
APPEARS IN
RELATED QUESTIONS
For 10 pairs of observations on two variables X and Y, the following data are available:
`sum(x-2)=30, sum(y-5)=40, sum(x-2)^2=900, sum(y-5)^2=800, sum(x-2)(y-5)=480`
Find the correlation coefficient between X and Y.
Find Karl Pearson’s coefficient of correlation between the variables X and Y for the following data
X | 11 | 7 | 9 | 5 | 8 | 6 | 10 |
Y | 10 | 8 | 6 | 5 | 9 | 7 | 11 |
Calculate from `e_0^0,e_1^0,e_2^0` from the following data :
Age x | 0 | 1 | 2 |
`l_x` | 1000 | 900 | 700 |
`T_x` | - | - | 11500 |
Find Karl Pearson's correlation coefficient for the following data :
X | 3 | 2 | 1 | 5 | 4 |
Y | 8 | 4 | 10 | 2 | 6 |
A train travelled between two stations. The distance and time were recorded as below:
Distance (Km) | 80 | 120 | 160 | 200 | 240 |
Time (Hr) | 2 | 3 | 4 | 5 | 6 |
Draw scatter diagram and identify the type of correlation.
If r = 0.5, σx = 1 and σy = 4, then find Cov.(X,Y).
Given that r = 0.4 , `Σ(x - barx)(y - bary) = 108 , σ_y = 3 and Σ(x - barx)^2 = 900` . Find the number of pairs of observations.
The equations of the two regression lines are 2x + 3g - 6 = 0 and 5x + 7g - 12 = 0
Find: (a) Correlation coefficient.
(b) `sigma_x/sigma_y`
If Σd2 = 66 and n = 10 then find the rank correlation coefficient.
Calculate the coefficient of correlation between X and Y series from the following data :
`n = 15 ,bar x = 25, bary = 18, σ_x = 3.01, σ_y = 3.03,`
`sum ("x"_i - bar x) ("y"_i - bar y) = 122`
Compute rank correlation coefficient for the following data :
Rx | 1 | 2 | 3 | 4 | 5 | 6 |
Ry | 6 | 3 | 2 | 1 | 4 | 5 |
If the rank correlation coefficient is `2/3` and `Σ"d"_1^2` = 55` , then find the number of pairs of observations. (Assume that no rank is repeated.)
A sample of 5 items is taken from the production of a firm. Length and weight of the five items arc given below :
Length (cm) | 3 | 4 | 6 | 7 | 10 |
Weight (gm) | 9 | 11 | 14 | 15 | 16 |
Calculate Karl Pearson's coefficient of correlation between the length and weight and interpret the result.