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Question
In kite WEAR, ∠WEA = 70° and ∠ARW = 80°. Find the remaining two angles.
Solution
Given, In a kite WEAR, ∠WEA = 70°, ∠ARW = 80°
Now, by the interior angle sum property of a quadrilateral,
∠RWE + ∠WEA + ∠EAR + ∠ARW = 360°
⇒ ∠RWE + 70 + ∠EAR + 80° = 360°
⇒ ∠RWE + EAR = 360° – 150°
⇒ ∠RWE + ∠EAR = 210° ...(i)
Now, ∠RWA = ∠RAW [∵ RW = RA] ...(ii)
And ∠AWE = ∠WAE [∵ WE = AE] ...(iii)
On adding equations (ii) and (iii), we get
∠RWA + ∠AWE = ∠RAW + ∠WAE
⇒ ∠RWE = ∠RAE
From equation (i),
2∠RWE = 210°
∠RWE = 105°
⇒ ∠RWE = ∠RAE = 105°
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