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In parallelogram PQRS, ∠Q = (4x – 5)° and ∠S = (3x + 10)°. Calculate: ∠Q and ∠R. - Mathematics

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Question

In parallelogram PQRS, ∠Q = (4x – 5)° and ∠S = (3x + 10)°. Calculate: ∠Q and ∠R.

Sum

Solution

In parallelogram PQRS,

∠Q = (4x – 5)° and ∠S = (3x + 10)°

opposite ∠s of //gm are equal.

∠Q = ∠S

4x – 5 = 3x + 10

4x – 3x = 10+5

x = 15

∠Q = 4x – 5 =4 x 15 – 5 = 55°

Also ∠Q + ∠R = 180°

55° + ∠R = 180°

∠R = 180°–55° = 125°

∠Q = 55° ; ∠R = 125°

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Chapter 17: Special Types of Quadrilaterals - Exercise 17 [Page 198]

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Selina Concise Mathematics [English] Class 8 ICSE
Chapter 17 Special Types of Quadrilaterals
Exercise 17 | Q 2 | Page 198
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