हिंदी
सी.आई.एस.सी.ई.आईसीएसई ICSE Class 8

In parallelogram PQRS, ∠Q = (4x – 5)° and ∠S = (3x + 10)°. Calculate: ∠Q and ∠R. - Mathematics

Advertisements
Advertisements

प्रश्न

In parallelogram PQRS, ∠Q = (4x – 5)° and ∠S = (3x + 10)°. Calculate: ∠Q and ∠R.

योग

उत्तर

In parallelogram PQRS,

∠Q = (4x – 5)° and ∠S = (3x + 10)°

opposite ∠s of //gm are equal.

∠Q = ∠S

4x – 5 = 3x + 10

4x – 3x = 10+5

x = 15

∠Q = 4x – 5 =4 x 15 – 5 = 55°

Also ∠Q + ∠R = 180°

55° + ∠R = 180°

∠R = 180°–55° = 125°

∠Q = 55° ; ∠R = 125°

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 17: Special Types of Quadrilaterals - Exercise 17 [पृष्ठ १९८]

APPEARS IN

सेलिना Concise Mathematics [English] Class 8 ICSE
अध्याय 17 Special Types of Quadrilaterals
Exercise 17 | Q 2 | पृष्ठ १९८
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×