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Question
In \[\ce{PO^{3-}4}\] ion the formal charge on the oxygen atom of P – O bond is ______.
Options
+ 1
– 1
– 0.75
+ 0.75
Solution
In \[\ce{PO^{3-}4}\] ion the formal charge on the oxygen atom of P – O bond is – 1.
Explanation:
Formal charge of the atom in the molecule or ion = (Number of valence electrons in free atom) – (Number of lone pair electrons + 1/2 Number of bonding electrons)
\[\ce{PO^{3-}4}\] :
\[\begin{array}{cc}
\ce{^-O}\\
\phantom{.....}\backslash\\
\phantom{.............}\ce{P = O}\\
\phantom{......}/\phantom{.}|\\
\phantom{.....}\ce{^-O}\phantom{..}\ce{O-}
\end{array}\]
For charge on oxygen = `6 - (6 + 1/2 xx 2) = 6 - 7 = - 1`
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