English

Ionic or Electrovalent Bond

Advertisements

Topics

  • Ionic bond or Electrovalent bond
  • Mechanism of formation of ionic bond
  • Lattice enthalpy
  • Factors affecting the formation of an ionic bond
    i) Low ionization enthalpy
    ii) High negative electron gain enthalpy
    iii) Large lattice enthalpy
  • Characteristics of ionic or electrovalent compounds
  • Difference between ionic bond and covalent bond
  • Covalent character in ionic bond
  • Fajan's rules

Introduction of Ionic Bond:

An ionic bond is a type of chemical bond formed through the transfer of electrons from one atom to another. It typically occurs between a metal and a nonmetal.

  • In this process, the metal atom loses one or more electrons to become a positively charged ion (cation), while the nonmetal gains these electrons to become a negatively charged ion (anion).
  • The electrostatic force of attraction between the oppositely charged ions holds them together in a stable structure, forming an ionic bond.
  • Ionic bonds are responsible for the formation of ionic compounds, such as sodium chloride (NaCl).
  • These compounds exhibit unique properties, including high melting and boiling points, solubility in water, and the ability to conduct electricity in molten or aqueous states.
  • The ionic bond allows atoms to achieve a stable electron configuration, often following the octet rule, which makes them energetically stable.

Formation of Ionic Bonds

(a) Formation of Ionic Bond in NaCl (Sodium Chloride):

  1. Sodium (Na): Atomic number 11, configuration 2,8,1. It has 1 valence electron in its outermost shell (M shell).
  2. Chlorine (Cl): Atomic number 17, configuration 2,8,7. It has 7 valence electrons and needs 1 more electron to complete its octet.
  3. Sodium loses 1 electron, becoming a Na⁺ cation (positively charged ion). New configuration of Na⁺: 2,8 (stable octet).
  4. Chlorine gains the electron lost by sodium, becoming a Cl⁻ anion (negatively charged ion). New configuration of Cl⁻: 2, 8, 8 (stable octet).
  5. The oppositely charged ions (Na⁺ and Cl⁻) are held together by the electrostatic force of attraction, forming an ionic bond.
  6. The compound formed is sodium chloride (NaCl).

Formation of Ionic bond of NaCl 

(b) Formation of Ionic Bond in MgCl₂ (Magnesium Chloride):

  1. Magnesium (Mg): Atomic number = 12, electronic configuration = 2, 8, 2.
  2. Magnesium has 2 valence electrons in its outermost shell. It needs to lose 2 electrons to achieve a stable octet configuration.
  3. Chlorine (Cl): Atomic number = 17, electronic configuration = 2, 8, 7.
  4. Chlorine has 7 valence electrons in its outermost shell. Each chlorine atom needs 1 electron to complete its octet.
  5. Magnesium loses 2 electrons, forming a Mg²⁺ cation with a stable configuration of 2, 8.
  6. Each chlorine atom gains 1 electron from magnesium to form a Cl⁻ anion with a stable configuration of 2, 8, 8.

Mg → Mg²⁺ + 2e⁻

Cl + e⁻ → Cl⁻

Magnesium loses 2 electrons, and these are gained by 2 chlorine atoms.

Mg²⁺ + 2Cl⁻ → MgCl₂

Formation of Ionic bond in MgCl₂ molecule

(c) Formation of Ionic Bond in KF (Potassium Fluoride):

  1. Potassium (K): Atomic number = 19, electronic configuration = 2, 8, 8, 1.
  2. Potassium has 1 valence electron in its outermost shell. And it needs to lose 1 electron to achieve a stable octet configuration.
  3. Fluorine (F): Atomic number = 9, electronic configuration = 2, 7.
  4. Fluorine has 7 valence electrons in its outermost shell. And it needs to gain 1 electron to complete its octet.
  5. Potassium loses 1 electron, forming a K⁺ cation with a stable configuration of 2, 8, 8.
  6. Fluorine gains 1 electron from potassium to form a F⁻ anion with a stable configuration of 2, 8.

K → K⁺ + e⁻

F + e⁻ → F⁻

Potassium loses 1 electron, and fluorine gains 1 electron, ensuring charge balance:

K⁺ + F⁻ → KF

Formation of Ionic bond in KF molecule

(d) Formation of Ionic Bond in CaO (Calcium Oxide):

  1. Calcium (Ca): Atomic number = 20, electronic configuration = 2, 8, 8, 2.
  2. Calcium has 2 valence electrons in its outermost shell. And it needs to lose 2 electrons to achieve a stable octet configuration.
  3. Oxygen (O): Atomic number = 8, electronic configuration = 2, 6.
  4. Oxygen has 6 valence electrons in its outermost shell. And it needs to gain 2 electrons to complete its octet.
  5. Calcium loses 2 electrons, forming a Ca²⁺ cation with a stable configuration of 2, 8, 8.
  6. Oxygen gains 2 electrons from calcium to form an O²⁻ anion with a stable configuration of 2, 8.

Ca → Ca²⁺ + 2e⁻

O + 2e⁻ → O²⁻

Calcium loses 2 electrons, and oxygen gains 2 electrons, ensuring charge balance:

Formation of Ionic bond in CaO molecule

Properties of Ionic Compounds

Melting point and boiling point of some ionic compounds:

Ionic Compound Melting Point (K) Boiling Point (K)
NaCl 1074 1686
LiCl 887 1600
CaCl₂ 1045 1900
CaO 2850 3120
MgCl₂ 981 1685
  1. Ionic compounds are solid and hard due to the strong electrostatic force between positive and negative ions but are generally brittle, breaking when pressure is applied.
  2. They have high melting and boiling points because a large amount of energy is needed to overcome the strong ionic bonds.
  3. Ionic compounds are typically soluble in water, as water's polarity helps separate the ions, but they are insoluble in non-polar solvents like kerosene or petrol.
  4. In solid form, ionic compounds do not conduct electricity because the ions are fixed in place in the crystal lattice and cannot move.
  5. In molten form or aqueous solutions, ionic compounds conduct electricity as the ions are free to move and carry electric charge.
  6. Ionic compounds are characterised by a rigid lattice structure, which provides stability but limits flexibility.
If you would like to contribute notes or other learning material, please submit them using the button below.

Shaalaa.com | Ionic bond formation

Shaalaa.com


Next video


Shaalaa.com


Ionic bond formation [00:14:42]
S
Series: series 1
0%


Advertisements
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×