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Question
In previous questions 3 and 4, what is the net power absorbed by each circuit over a complete cycle. Explain your answer.
Solution
In the inductive circuit,
rms value of current, I = 15.92 A
rms value of voltage, V = 220 V
Hence, the net power absorbed can be obtained by the relation,
P = VI cos `phi`
Where,
`phi` = Phase difference between V and I
For a pure inductive circuit, the phase difference between alternating voltage and current is 90°, i.e., `phi` = 90°.
Hence, P = 0, i.e., the net power is zero.
In the capacitive circuit,
rms value of current, I = 2.49 A
rms value of voltage, V = 110 V
Hence, the net power absorbed can be obtained as:
P = VI Cos `phi`
For a pure capacitive circuit, the phase difference between alternating voltage and current is 90°, i.e., `phi` = 90°.
Hence, P = 0, i.e., the net power is zero.
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