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In the adjoining diagram, a tilted right circular cylindrical vessel with base diameter 7 cm contains a liquid. When placed vertically, the height of the liquid in the vessel - Mathematics

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Question

In the adjoining diagram, a tilted right circular cylindrical vessel with base diameter 7 cm contains a liquid. When placed vertically, the height of the liquid in the vessel is the mean of two heights shown in the diagram. Find the area of wet surface, when the cylinder is placed vertically on a horizontal surface. (Use π = `22/7`).

Sum

Solution

The cylinder has a base diameter of 7 cm, so the radius r is:

r = `7/2 = 3.5 " cm"`

The heights of the liquid when tilted are h1 = 1 and h2 ​= 6 cm.

∴ h = `(h_1 + h_2)/2`

`\implies` h = `1/2(1 + 6)`,

`\implies` h = `7/2`

`\implies` h = 3.5 cm

Area of wet surface = πr2 + 2πrh

Area of base = πr2 

= `22/7 xx (3.5)^2`

= 38.5 cm2

Lateral surface area = 2πrh

= `2 xx 22/7 xx 3.5 xx 3.5`

= `2  xx 22/7 xx 12.25`

= 77 cm2

Total wet surface area = Area of base + Lateral area

= 38.5 cm+ 77 cm2

= 115.5 cm2

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