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Tamil Nadu Board of Secondary EducationHSC Science Class 12

In the circuit shown in the figure, the BJT has a current gain (β) of 50. For an emitter-base voltage VEB = 600 mV, calculate the emitter-collector voltage VEC (in volts). - Physics

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Question

In the circuit shown in the figure, the BJT has a current gain (β) of 50. For an emitter-base voltage VEB = 600 mV, calculate the emitter-collector voltage VEC (in volts).

Numerical

Solution

β = 50

VEB = 600 × 10−3 V

RB = 60 k Ω

RC = 500 k Ω

VB = VE – VEB

= 3 – 0.6

= 2.4 V

IB = `"V"_"B"/"R"_"B"`

= `2.4/(60 xx 10^9)`

= 0.04 × 103 A

IB = 40 µA

IC = β IB

= 50 × 40 × 106

IC = 2 mA

VC = IC RC = 500 IC

= 500 × 2 × 103

VEC = VE – VC

= 3 – 1

= 2 V

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Bipolar Junction Transistor (BJT)
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Chapter 10: Electronics and Communication - Evaluation [Page 249]

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Samacheer Kalvi Physics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 10 Electronics and Communication
Evaluation | Q IV. 5. | Page 249

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