Advertisements
Advertisements
Question
In the circuit shown in the figure, the BJT has a current gain (β) of 50. For an emitter-base voltage VEB = 600 mV, calculate the emitter-collector voltage VEC (in volts).
Solution
β = 50
VEB = 600 × 10−3 V
RB = 60 k Ω
RC = 500 k Ω
VB = VE – VEB
= 3 – 0.6
= 2.4 V
IB = `"V"_"B"/"R"_"B"`
= `2.4/(60 xx 10^9)`
= 0.04 × 10−3 A
IB = 40 µA
IC = β IB
= 50 × 40 × 10−6
IC = 2 mA
VC = IC RC = 500 IC
= 500 × 2 × 10−3
VEC = VE – VC
= 3 – 1
= 2 V
APPEARS IN
RELATED QUESTIONS
The light emitted in an LED is due to
Ve, Vb, and Ve are emitter, base, and collector voltage respectively for npn transistor in CE mode. Amplifier works for the combination of biasing voltage equal to ______.
In an npn transistor, the collector current is 24 mA. If 80% of electrons reach collector, its base current in mA is ______.
In a common emitter amplifier circuit using an n-p-n transistor, the phase difference between the input and the output voltages will be: ____________.
A pnp transistor is used in common-emitter mode. If a change of 40 µA in base current brings a change of 2 µA in collector current with 0.04 V in base-emitter voltage, then the input resistance is ____________.
In transistor amplifier, base-emitter junction is forward biased and collector emitter junction is reverse biased. The current gain is ______.
In common emitter amplifier, a change of 0.2 mA in the base current causes a change of 5 mA in the collector current. If input resistance is 2K `Omega` and voltage gain is 75, the load resistance used in the circuit is ______.
In the common-emitter configuration of a transistor, the current gain is more than 1 because [lb, le, and lc are base, emitter, and collector currents respectively] ______
The transfer ratio of a transistor is 50. The input resistance of the transistor when used in the CE configuration is 1K Ω. The peak value for an AC input voltage of 0.01 V of collector current is ______.
In a CE amplifier, the current gain is 80 and the emitter current is 9 mA. The base current is ______.