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Question
In the figure, DE || AC and DC || AP. Prove that `"BE"/"EC" = "BC"/"CP"`
Solution
In ΔABC, DE || AC
∴ `"BE"/"EC" = "BD"/"DA"` ......(i)(By Basic Proportionality theorem)
In ΔABP, CD || AP
∴ `"BC"/"CP" = "BD"/"DA"`.......(ii)(By Proportionality theorem)
From (i) and (ii)
`"BE"/"EC" = "BC"/"CP"`.
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