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Question
In the given figure, BAC is a straight line.
Find:
(i) x
(ii) ∠AOB
(iii) ∠BOC
Solution
∵ ∠AOB and ∠COB are linear pairs
∴ ∠AOB + ∠COB = 180°
⇒ x + 25° + 3x + 15° = 180°
⇒ 4x + 40° = 180°
⇒ 4x = 180°− 40° = 140°
(i) ⇒ x =`(140°)/4=35°`
Hence, x = 35°
(ii) ∠AOB = x + 25° = 35° + 25° = 60°
(iii) ∠BOC = 3x + 15° = 3 × 35° + 15°
= 105° + 15° = 120°
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