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Question
In the given figure, ∠CAB = 25°, find ∠BDC, ∠DBA and ∠COB
Solution
In ΔACP,
∠ACP = 180° – (25° + 90°)
= 180° – 115°
= 65°
∠CBA = ∠CAB = 25° ...[Both the angles are standing in the same base]
∠DBA = 65° ...[∠DBA and ∠BCA standing in the same base]
∠COB = 50°
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