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Question
Find the value of x in the given figure.
Solution
∠B = 180° – 120° .....(Sum of the opposite angles of a quadrilateral are supplementary)
∠B = 60°
∠BCA = 90° ...(Angle in a semicircle)
∠BAC + ∠B + ∠BCA = 180°
x + 60° + 90° = 180°
x + 150° = 180°
x = 180° – 150°
= 30°
The value of x = 30°
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Solution:
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