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Question
In the given figure, prove that: BD = BC.
Solution
Proof:
In right Δ ABD and Δ ABC
Side AB = Side AB ...................(common)
Hypotenuse AD = Hypotenuse AC ...............(given)
∴ Δ ABD ≅ Δ ABC ................(R.H.S. Axiom)
Hence BD = BC .................(c.p.c.t.)
Hence proved.
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