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Question
In the parking lot shown, the lines that mark the width space are parallel. If ∠1 =(x + 39)°, ∠2 = (2x – 3y)° find x and y
Solution
From the picture
∠2 + 65° = 180° ...[Sum of interior angles on the same side of a transversal]
x + 39° + 65° = 180°
x + 104° = 180°
x + 104° – 104° = 180° – 104°
x = 76°
Also from the picture
∠1 = 65° ...[alternate exterior angles]
2x – 3y = 65°
2(76) – 3y = 65°
152° – 3y = 65°
152° – 3y – 152° = 65 – 152°
– 3y = – 87
y = `(-87)/(-3)`
y = 29°
x = 76°, y = 29°
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