Advertisements
Advertisements
Question
In trapezium ABCD with AB || CD, if ∠A = 100°, then ∠D = ______.
Solution
In trapezium ABCD with AB || CD, if ∠A = 100°, then ∠D = 80°.
Explanation:
In a trapezium, we know that, the angles on either side of the base are supplementary.
So, In trapezium ABCD, given AB || CD
∴ ∠A + ∠D = 180°
⇒ 100° + ∠D = 180°
⇒ ∠D = 180° – 100°
∴ ∠D = 80°
APPEARS IN
RELATED QUESTIONS
In `square`ABCD, side BC || side AD, side AB ≅ side DC If ∠A = 72° then find the measure of ∠B and ∠D.
In the given figure CE || DB then the value of x° is
Which of the following figures satisfy the following property?
- Only one pair of sides are parallel.
Every trapezium is a parallelogram.
Every rhombus is a trapezium.
Find the value of x in the trapezium ABCD given below.
ABCD is a trapezium such that AB || CD, ∠A : ∠D = 2 : 1, ∠B : ∠C = 7 : 5. Find the angles of the trapezium.
In the following figure, AB || DC and AD = BC. Find the value of x.
Construct a trapezium RISK in which RI || KS, RI = 7 cm, IS = 5 cm, RK = 6.5 cm and ∠I = 60°.
Construct a trapezium ABCD where AB || CD, AD = BC = 3.2 cm, AB = 6.4 cm and CD = 9.6 cm. Measure ∠B and ∠A.
[Hint: Difference of two parallel sides gives an equilateral triangle.]
