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Question
In triangle ABC; angle A = 90o, side AB = x cm, AC = (x + 5) cm and area = 150 cm2. Find the sides of the triangle.
Solution
The area of the triangle is given as 150 sq.cm
`1/2 xx x xx ( x + 5 ) = 150`
x2 + 5x - 300 = 0
( x + 20 )( x - 15 ) = 0
x = 15
Hence AB = 15cm, AC = 20 cm and
BC = `sqrt( 15^2 + 20^2 )` = 25 cm.
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