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Question
In what ratio is the line joining (2, -1) and (-5, 6) divided by the y axis ?
Solution
Let the point P (0, y) lies on y-axis which divides the line segment AB in the ratio k : 1.
Coordinates of P are ,
0 = `(-5 "k" + 2)/("k" + 1) , "y" = (6"k" - 1)/("k" + 1)`
⇒ 5 k = 2
⇒ k = `2/5`
Hence, the required ratio is 2 : 5.
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Activity:
∴ By section formula,
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What is the ratio in which the line segment joining (2, -3) and (5, 6) is divided by x-axis?
