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Question
In young 's double slit experiment the two coherent sources have different amplitudes. If the ratio of maximum intensity to minimum intensity is 16 : 1, then the ratio of amplitudes of the two source will be _______.
Options
4 : 1
5 : 3
1 : 4
1 : 16
Solution
In young 's double slit experiment the two coherent sources have different amplitudes. If the ratio of maximum intensity to minimum intensity is 16 : 1, then the ratio of amplitudes of the two source will be 5 : 3.
Explanation:
`"I"_"max"/"I"_"min" = 16/1`
`"I"_"max"/"I"_"min" = ("a"_1 + "a"_2)^2/("a"_1 - "a"_2)^2 = 16/1`
`"I"_"max"/"I"_"min" = 16/1`
`therefore ("a"_1 + "a"_2)/("a"_1 - "a"_2) = 4/1`
∴ a1 + a2 = 4a1 - 4a2
∴ 3a1 = 5a2
∴ `"a"_1/"a"_2 = 5/3`
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