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Question
Integrate the following with respect to x.
`(2x + 5)/(x^2 + 5x - 7)`
Solution
`int (2x + 5)/(x^2 + 5x - 7) "d"x`
`int 1/x "d"x`
= log |z| + c
= log |x2 + 5x – 7| + c
Take z = x2 + 5x – 7
`("d"z)/("d"x)` = 2x + 5
dz = (2x + 5) dx
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