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Question
It takes 60 days for 10 machines to dig a hole. Assuming that all machines work at the same speed, how long will it take 30 machines to dig the same hole?
Solution
Let the number of days required be x.
Number of machines | 10 | 30 |
Number of days | 60 | x |
As the number of machines increases it takes less days to complete the work
∴ They are in inverse proportion, x1y1 = x2y2
10 × 60 = 30 × x
x = `(10 xx 60)/30`, x = 20
It takes 20 days to dig the hole
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