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Question
Let A = `[(1, 2),(-1, 3)]`, B = `[(4, 0),(1, 5)]`, C = `[(2, 0),(1, -2)]` and a = 4, b = –2. Show that: (bA)T = bAT
Solution
We have,
A = `[(1, 2),(-1, 3)]`
B = `[(4, 0),(1, 5)]`
C = `[(2, 0),(1, -2)]`
And a = 4, b = –2
(bA)T = `[(-2, -4),(2, -6)]^"T"` .....[∵ b = –2]
= `[(-2, 2),(-4, -6)]`
And AT = `[(1, -1),(2, 3)]`
∴ bAT = `[(-2, 2),(-4, -6)]`
= (bA)T
Hence proved.
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