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Question
Let A = `[(1, 2),(-1, 3)]`, B = `[(4, 0),(1, 5)]`, C = `[(2, 0),(1, -2)]` and a = 4, b = –2. Show that: (AT)T = A
Solution
We have,
A = `[(1, 2),(-1, 3)]`
B = `[(4, 0),(1, 5)]`
C = `[(2, 0),(1, -2)]`
And a = 4, b = –2
AT = `[(1, 2),(-1, 3)]^"T"`
= `[(1, -1),(2, 3)]`
∴ (AT)T = `[(1, -1),(2, 3)]^"T"`
= `[(1, 2),(-1, 3)]`
= A
Hence proved.
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