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Question
Light enters from air into diamond which has a refractive index of 2.42. Calculate the speed of light in diamond. The speed of light in air is 3.0 × 108 ms−1.
Solution
We know:
Refractive index = Speed of light in air/Speed of light in diamond
Let X be the speed of light in diamond. Now, we have:
2.42 = 3.0 × 108 ms-1 / X
X = 1.24 × 108 ms-1
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RELATED QUESTIONS
A ray of light travelling in air enters obliquely into water. Does the light ray bend towards the normal or away from the normal? Why?
You are given kerosene, turpentine and water. In which of these does the light travel fastest? Use the information given in Table.
| Material medium |
Refractive index | Material medium | Refractive index |
| Air | 1.0003 | Canada Balsam | 1.53 |
| Ice | 1.31 | – | – |
| Water | 1.33 | Rock salt | 1.54 |
| Alcohol | 1.36 | – | – |
| Kerosene | 1.44 | Carbon disulphide | 1.63 |
| Fused quartz |
1.46 | Dense flint glass |
1.65 |
| Turpentine oil | 1.47 | Ruby | 1.71 |
| Benzene | 1.50 | Sapphire | 1.77 |
| Crown glass |
1.52 | Diamond | 2.42 |
A ray of light travelling in water falls at right angles to the boundary of a parallel-sided glass block. The ray of light:
(a) is refracted towards the normal
(b) is refracted away from the normal
(c) does not get refracted
(d) is reflected along the same path
Which has higher refraction index : water of glass?
How is the refractive index of a material related to the speed of light in it?
State and explain the laws of refraction of light with the help of a labelled diagram.
Fill in the blank and Explain the completed sentences.
Refractive index depends on the ______ of light.
n = _______. This law is also called as Snell’s law.
What happens when a light ray passes from a rarer medium to a denser medium?
A light ray enters from medium A to medium B as shown in the figure.
If the speed of light in medium A is `v_a` and in medium B is `v_b`, what is the refractive index of B with respect to A.
