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Question
LPG stands for liquefied petroleum gas. Varieties of LPG are marketed including a mixture of propane (60%) and butane (40%). If 10 litres of this mixture is burnt, find the total volume of carbon dioxide gas added to the atmosphere. Combustion reaction can be represented as:
\[\ce{C3H8_{(g)} + 5O2_{(g)} -> 3CO2_{(g)} + 4H2O_{(g)}}\]
\[\ce{2C4H10_{(g)} + 13O2_{(g)} -> 8CO2_{(g)} + 10H2O_{(g)}}\]
Solution
% of propane = 60%
% of butane = 40%
Total volume of the mixture = 10 litres
Propane = `60/100 xx 10` = 6 litres
Butane = `40/100 xx 10` = 4 litres
(i) Combustion of propane:
| C3H8(g) | + | 5O2(g) | → | 3CO2(g) | + | 4H2O(g) |
| 1 vol. | 3 vol. | |||||
| 6 litres | ? |
1 vol of propane releases 3 vol of CO2
6 litres of propane releases `3/1 xx 6` litres
(ii) Combustion of butane:
| 2C4H10(g) | + | 13O2(g) | → | 8CO2(g) | + | 10H2O(g) |
| 2 vol. | 8 vol. | |||||
| 1 vol. | 4 vol. | |||||
| 4 litres | ? |
2 vol of butane releases 8 vol of CO2
4 litres of butane releases `8/2 xx 4` = 16 litres
Total CO2 released O2 = 18 L + 16 L
= 34 litres of CO2 gas is added to the atmosphere.
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