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Question
The reaction between the red lead and hydrochloric acid is given below:
\[\ce{Pb3O4 + 8HCl -> 3PbCl2 + 4H2O + Cl2}\]
Calculate the mass of lead chloride formed by the action of the 6.85 g of red lead.
Solution
Molecular mass of Pb3O4 = 3 207.2 + 4 16 = 685 g
685 g of Pb3O4 gives = 834 g of PbCl2
Hence, 6.85 g of Pb3O4 will give = `(6.85 xx 834)/685` = 8.34 g
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