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Question
The reaction between the red lead and hydrochloric acid is given below:
\[\ce{Pb3O4 + 8HCl -> 3PbCl2 + 4H2O + Cl2}\]
Calculate the mass of the chlorine.
Solution
685g of Pb3O4 gives = 71g of Cl2
Hence, 6.85 g of Pb3O4 will give = `(6.85 xx 71)/685` = 0.71 g
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