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Question
What volume of oxygen is required to burn completely a mixture of 22.4 dm3 of methane and 11 .2 dm3 of hydrogen in to carbon dioxide and steam? Equations of the reactions are given below:
CH4 + 2O2 → CO2 + 2H2O
2H2 + O2 → 2H2O
Solution
CH4 + 2O2 → CO2 + 2H2O
1 vol. 2 vol. 1 vol. 2 vol.
One volume of methane requires oxygen = 2 vol.
So, Vol. of oxygen used = 2 x 22.4 = 44.8 dm3
2H2 + O2 → 2H2O
2 vol. 1 vol. 2 vol.
2 volume of hydrogen needs one volume of oxygen
So, Volume of oxygen used = 22.4 / 2 = 11.2 dm3
Total volume of oxygen used = 44.8 + 11.2 = 56.0 dm3
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