Advertisements
Advertisements
Question
Make a the subject of formula S = `("a"("r"^"n" - 1))/("r" - 1)`
Solution
S = `("a"("r"^"n" - 1))/("r" - 1)`
⇒ S(r - 1) = a(rn - 1)
⇒ `("S"("r" - 1))/(("r"^"n" - 1)` = a
⇒ a = `("S"("r" - 1))/(("r"^"n" - 1)`.
APPEARS IN
RELATED QUESTIONS
Make d the subject of formula S = `"n"/(2){2"a" + ("n" - 1)"d"}`
Make R2 the subject of formula R2 = 4π(R12 - R22)
Make A the subject of formula R = `("m"_1"B" + "m"_2"A")/("m"_1 + "m"_2)`
Make h the subject of the formula R = `"h"/(2)("a" - "b")`. Find h when R = 108, a = 16 and b = 12.
Make a the subject of the formula S = `"n"/(2){2"a" + ("n" - 1)"d"}`. Find a when S = 50, n = 10 and d = 2.
Make y the subject of the formula `x/"a" + y/"b" `= 1. Find y, when a = 2, b = 8 and x = 5.
Make m the subject of the formula x = `"my"/(14 - "mt")`. Find m, when x = 6, y = 10 and t = 3.
Make z the subject of the formula y = `(2z + 1)/(2z - 1)`. If x = `(y + 1)/(y - 1)`, express z in terms of x, and find its value when x = 34.
The total energy E possess by a body of Mass 'm', moving with a velocity 'v' at a height 'h' is given by: E = `(1)/(2) "m" "u"^2 + "mgh"`. Find m, if v = 2, g = 10, h = 5 and E = 104.
"Area A oof a circular ring formed by 2 concentric circles is equal to the product of pie and the difference of the square of the bigger radius R and the square of the bigger radius R and the square of the smaller radius r. Express the above statement as a formula. Make r the subject of the formula and find r, when A = 88 sq cm and R = 8cm.