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MnOX42− undergoes disproportionation reaction in acidic medium but MnOX4− does not. Give reason. - Chemistry

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Question

\[\ce{MnO^{2-}4}\] undergoes disproportionation reaction in acidic medium but \[\ce{MnO^{-}4}\] does not. Give reason.

Short Note

Solution

In \[\ce{MnO^{2-}4}\], Mn is in highest oxidation state that is +7 hence here manganese cannot undergo oxidation that is why disproportionate is not possible whereas in \[\ce{MnO^{2-}4}\] manganese is in +6 oxidation state which can be oxidized as well as reduced.

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Oxidation Number - Types of Redox Reactions
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Chapter 8: Redox Reactions - Multiple Choice Questions (Type - I) [Page 107]

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NCERT Exemplar Chemistry [English] Class 11
Chapter 8 Redox Reactions
Multiple Choice Questions (Type - I) | Q 18 | Page 107

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