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Question
Find out the oxidation number of chlorine in the following compounds and arrange them in increasing order of oxidation number of chlorine.
\[\ce{NaClO4, NaClO3, NaClO, KClO2, Cl2O7, ClO3, Cl2O, NaCl, Cl2 , ClO2}\].
Which oxidation state is not present in any of the above compounds?
Solution
We can calculate the oxidation states by:
\[\ce{NaClO4}\] Oxidation no. of chlorine = +7
Suppose oxidation number of chlorine is x then, 1 + x + 4 × (−2) = 0
∴ x – 7 = 0
x = +7
We can calculate, the oxidation states, as given below:
\[\ce{NaClO3}\] Oxidation no. of chlorine = +5
\[\ce{NaClO}\] Oxidation no. of chlorine = +1
\[\ce{KClO2}\] Oxidation no. of chlorine = +3
\[\ce{Cl2O7}\] Oxidation no. of chlorine = +7
\[\ce{ClO3}\] Oxidation no. of chlorine = +6
\[\ce{Cl2O}\] Oxidation no. of chlorine = +1
\[\ce{NaCl}\] Oxidation no. of chlorine = −1
\[\ce{Cl2}\] Oxidation no. of chlorine = 0
\[\ce{ClO2}\] Oxidation no. of chlorine = +4.
Oxidation state (+2) is not present in any of the above compounds.
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