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Question
Mohit makes 8 full rounds of a rectangular field with length = 120 m and breadth = 75 m.
John makes 10 full rounds of a square field with each side 100 in. Find who covers larger distance and by how much?
Solution
Mohit
Length of the rectangular field = 120 m
Breadth of the rectangular field = 75 m
∴ Distance covered in one round (perimeter)
= 2(1 + b) = 2(120 + 75) = 390 m
Hence, distance covered in 8 rounds = 390 x 8 m = 3120 m
John
Side of the field = 100 m
∴ Distance covered in one round = 4 x a = 4 x 100 = 400 m
Hence, Distance covered in 10 rounds = 400 x 10 m = 4000 m
John a covers greater distance then Mohit by = (4000 - 3120) m = 880 m
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