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Question
Monica has a piece of Canvas whose area is 551 m2. She uses it to have a conical tent made, with a base radius of 7m. Assuming that all the stitching margins and wastage incurred while cutting, amounts to approximately 1 m2. Find the volume of the tent that can be made with it.
Solution
Given that,
Area of canvas ` 551m^2` and area of the canvas lost in wastage is `1m^2`
∴ area of canvas available for making the tent is `(551-1)m^2=550m^2.`
SA of tent =`550m^2` required base radius of conical tent= 7m
CSA of tent=`550m^2 `
`pirl=550m^2`
`⇒22/7xx7xxl=550`
`⇒l=550/22=25m `
Now, WKT
`l^2=r^2+h^2`
`⇒(25)^2-(7)^2=h^2 `
`⇒ h=sqrt(625-49)`
`=sqrt576=24m`
So, the volume of the conical tent =`1/3pir^2h`
`= 1/3xx3.14xx(7xx7)(24)m^3=1232m^3`
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