Advertisements
Advertisements
Question
Multiply the following:
abc, (bc + ca)
Solution
We have,
abc and (bc + ca)
∴ abc × (bc + ca) = abc × bc + abc × ca
= ab2c2 + a2bc2
APPEARS IN
RELATED QUESTIONS
Find the product of the following pair of monomial.
− 4p, 7p
Obtain the volume of a rectangular box with the following length, breadth, and height, respectively.
a, 2b, 3c
Obtain the product of a, 2b, 3c, 6abc.
Express each of the following product as a monomials and verify the result for x = 1, y = 2:
\[\left( \frac{4}{9}ab c^3 \right) \times \left( - \frac{27}{5} a^3 b^2 \right) \times \left( - 8 b^3 c \right)\]
Multiply: 2a2 − 5a − 4 and −3a
Multiply: 2m2 − 3m − 1 and 4m2 − m − 1
| Length | breadth | height | |
| (i) | 2ax | 3by | 5cz |
| (ii) | m2n | n2p | p2m |
| (iii) | 2q | 4q2 | 8q3 |
Multiply (4x2 + 9) and (3x – 2)
Volume of a rectangular box (cuboid) with length = 2ab, breadth = 3ac and height = 2ac is ______.
Multiply the following:
–7pq2r3, –13p3q2r
