English

Name the type of triangle formed by the points A(–5, 6), B(–4, –2) and C(7, 5). - Mathematics

Advertisements
Advertisements

Question

Name the type of triangle formed by the points A(–5, 6), B(–4, –2) and C(7, 5).

Sum

Solution

To find the type of triangle, first we determine the length of all three sides and see whatever condition of triangle is satisfy by these sides.

Now, using distance formula between two points,

AB = `sqrt((-4 + 5)^2 + (-2 - 6)^2`   ...`[∵ d = sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)]`

= `sqrt((1)^2 + (-8)^2`

= `sqrt(1 + 64)`

= `sqrt(65)`

BC = `sqrt((7 + 4)^2 + (5 + 2)^2`

= `sqrt((11)^2 + (7)^2`

= `sqrt(121 + 49)`

= `sqrt(170)`

And CA = `sqrt((-5 - 7)^2 + (6 - 5)^2`

= `sqrt((-12)^2 + (1)^2`

= `sqrt(144 + 1)`

= `sqrt(145)`

We see that,

AB ≠ BC ≠ CA

And not hold the condition of Pythagoras in a ΔABC.

i.e., (Hypotenuse)2 = (Base)2 + (Perpendicular)2

Hence, the required triangle is scalene because all of its sides are not equal i.e., different to each other.

shaalaa.com
  Is there an error in this question or solution?
Chapter 7: Coordinate Geometry - Exercise 7.3 [Page 83]

APPEARS IN

NCERT Exemplar Mathematics [English] Class 10
Chapter 7 Coordinate Geometry
Exercise 7.3 | Q 1 | Page 83

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

If A(4, 3), B(-1, y) and C(3, 4) are the vertices of a right triangle ABC, right-angled at A, then find the value of y.


If the point A(0, 2) is equidistant from the points B(3, p) and C(p, 5), find p. Also, find the length of AB.


If Q (0, 1) is equidistant from P (5, − 3) and R (x, 6), find the values of x. Also find the distance QR and PR.


Find the distance between the following pair of points:

 (a+b, b+c) and (a-b, c-b)


Find the centre of the circle passing through (6, -6), (3, -7) and (3, 3)


If A and B are the points (−6, 7) and (−1, −5) respectively, then the distance

2AB is equal to


Find the value of y for which the distance between the points A (3, −1) and B (11, y) is 10 units.


Find the distance between the following point :

(sec θ , tan θ) and (- tan θ , sec θ)


Find the distance between the following point :

(Sin θ - cosec θ , cos θ - cot θ) and (cos θ - cosec θ , -sin θ - cot θ)


Case Study -2

A hockey field is the playing surface for the game of hockey. Historically, the game was played on natural turf (grass) but nowadays it is predominantly played on an artificial turf.

It is rectangular in shape - 100 yards by 60 yards. Goals consist of two upright posts placed equidistant from the centre of the backline, joined at the top by a horizontal crossbar. The inner edges of the posts must be 3.66 metres (4 yards) apart, and the lower edge of the crossbar must be 2.14 metres (7 feet) above the ground.

Each team plays with 11 players on the field during the game including the goalie. Positions you might play include -

  • Forward: As shown by players A, B, C and D.
  • Midfielders: As shown by players E, F and G.
  • Fullbacks: As shown by players H, I and J.
  • Goalie: As shown by player K.

Using the picture of a hockey field below, answer the questions that follow:

If a player P needs to be at equal distances from A and G, such that A, P and G are in straight line, then position of P will be given by ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×