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Obtain the equivalent capacitance of the network shown in the figure. For a 300 V supply, determine the charge on each capacitor. - Physics

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Question

Obtain the equivalent capacitance of the network shown in the figure. For a 300 V supply, determine the charge on each capacitor.

 

Derivation

Solution

The equivalent capacitance = 2003 pF

charge on C4 = 2003×10-12×300=2×10-8 C,

the potential difference across C4 = 200×10-12×3003×100×10-12 = 200 V

potential difference across C1 = 300 - 200 = 100 V

charge on C1 = 100 × 10-12 × 100 = 1 × 10-8 C

potential difference across C2 and C3 series combination = 100 V

potential difference across C2 and C3 each = 50 V

charge on C2 and C3 each = 200 × 10-12 × 50 = 1 × 10-8 C

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