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Question
Offices in Delhi are open for five days in a week (Monday to Friday). Two employees of an office remain absent for one day in the same particular week. Find the probability that they remain absent on different days.
Solution
Total number of possible outcomes = 5 × 5 = 25
The possible outcomes are:
MM, MT, MW, MTh, MF, TM, TT, TW, TTh, TF, WM, WT, WW, WTh, WF, ThM, ThT, ThW, ThTh, ThF, FM, FT, FW, FTh, FF
P(absent on different days) = 1 – P(absent on same days)
= `1 - 1/5`
= `4/5`
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