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Question
On reaction with \[\ce{Cl2}\], phosphorus forms two types of halides ‘A’ and ‘B’. Halide A is yellowish-white powder but halide ‘B’ is colourless oily liquid. Identify A and B and write the formulas of their hydrolysis products.
Solution
A is \[\ce{PCl5}\] .....(It is yellowish white powder)
\[\ce{P4 + 10Cl2 -> 4PCl5}\]
B is \[\ce{PCl3}\] .....(It is a colourless oily liquid)
\[\ce{P4 + 6Cl2 -> 4PCl3}\]
Hydrolysis products are formed as follows:
\[\ce{PCl3 + 3H2O -> H3PO3 + 3HCl}\]
\[\ce{PCl5 + 4H2O -> H3PO4 + 5HCl}\]
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