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Question
Out of 1900 km, Vishal travelled some distance by bus and some by aeroplane. The bus travels with an average speed of 60 km/hr and the average speed of the aeroplane is 700 km/hr. It takes 5 hours to complete the journey. Find the distance, Vishal travelled by bus.
Solution
We know `"speed" = "distance"/"time"`
Average speed of bus = 60km/h.
Let the time taken in bus be x hours.
Average speed of plane = 700km/h.
Let the time taken in the plane be y hours.
Total distance covered = 1900 km
60x + 700y = 1900
⇒ 6x + 70y = 190
⇒ 3x + 35y = 95 ...(I)
It takes 5 hours to complete the journey so,
x + y = 5 ...(II)
Multiplying (II) with 3
3x + 3y = 15 ...(III)
Subtracting (III) from (I) we get
3x - 3x + 35y - 3y = 95 - 15
⇒ 32y = 80
⇒ y = `80/32`
⇒ y = 2.5
Putting the value of y = 2.5 in (II) we get
x + 2.5 = 5
x = 5 - 2.5
⇒ x = 2.5
Distance travelled by Vishal by bus = speed × time
= 60 × 2.5
= 150 km